Section 8.8Use the Complex Number System
Before you get started, take this readiness quiz.
Given the numbers \(-4,-\sqrt{7},0.\bar{5},\frac{7}{3},3,\sqrt{81},\) list the ⓐ rational numbers, ⓑ irrational numbers, ⓒ real numbers.
If you missed this problem, review Example 9.
ⓐ \(-4,0.\bar{5},\frac{7}{3},3,\sqrt{81};\) ⓑ \(\sqrt{7};\) ⓒ \(-4,-\sqrt{7},0.\bar{5},\frac{7}{3},3,\sqrt{81}\)
Multiply: \((x-3)(2x+5).\)
If you missed this problem, review Example 4.
\(2{x}^{2}-x-15\)
Rationalize the denominator: \(\frac{\sqrt{5}}{\sqrt{5}-\sqrt{3}}.\)
If you missed this problem, review Example 8.
\(\frac{5+\sqrt{15}}{2}\)
Evaluate the Square Root of a Negative Number
Whenever we have a situation where we have a square root of a negative number we say there is no real number that equals that square root. For example, to simplify \(\sqrt{-1},\) we are looking for a real number x so that x2 = –1. Since all real numbers squared are positive numbers, there is no real number that equals –1 when squared.
Mathematicians have often expanded their numbers systems as needed. They added 0 to the counting numbers to get the whole numbers. When they needed negative balances, they added negative numbers to get the integers. When they needed the idea of parts of a whole they added fractions and got the rational numbers. Adding the irrational numbers allowed numbers like \(\sqrt{5}.\) All of these together gave us the real numbers and so far in your study of mathematics, that has been sufficient.
But now we will expand the real numbers to include the square roots of negative numbers. We start by defining the imaginary unit \(i\) as the number whose square is –1.
The imaginary unit i is the number whose square is –1.
\[{i}^{2}=-1\,\text{or}\,i=\sqrt{-1}\]
We will use the imaginary unit to simplify the square roots of negative numbers.
If b is a positive real number, then
\[\sqrt{\text{-}b}=\sqrt{b}\,i\]
We will use this definition in the next example. Be careful that it is clear that the i is not under the radical. Sometimes you will see this written as \(\sqrt{\text{-}b}=i\sqrt{b}\) to emphasize the i is not under the radical. But the \(\sqrt{\text{-}b}=\sqrt{b}\,i\) is considered standard form.
Write each expression in terms of i and simplify if possible:
ⓐ \(\sqrt{-25}\) ⓑ \(\sqrt{-7}\) ⓒ \(\sqrt{-12}.\)
Rewrite each square root using \(\sqrt{\text{-}b}=\sqrt{b}\,i,\) then simplify the remaining square root.
ⓐ
ⓑ
ⓒ
| \(\sqrt{-25}\) | |
| Use the definition of the square root of negative numbers. | \(\sqrt{25}\,i\) |
| Simplify. | \(5i\) |
| \(\sqrt{-7}\) | |
| Use the definition of the square root of negative numbers. | \(\sqrt{7}i\) |
| Simplify. | Be careful that it is clear that \(i\) is not under the radical sign. |
| \(\sqrt{-12}\) | |
| Use the definition of the square root of negative numbers. | \(\sqrt{12}\,i\) |
| Simplify \(\sqrt{12}.\) | \(2\sqrt{3}\,i\) |
Write each expression in terms of i and simplify if possible:
ⓐ \(\sqrt{-81}\) ⓑ \(\sqrt{-5}\) ⓒ \(\sqrt{-18}.\)
ⓐ \(9i\) ⓑ \(\sqrt{5}i\) ⓒ \(3\sqrt{2}i\)
Write each expression in terms of i and simplify if possible:
ⓐ \(\sqrt{-36}\) ⓑ \(\sqrt{-3}\) ⓒ \(\sqrt{-27}.\)
ⓐ \(6i\) ⓑ \(\sqrt{3}i\) ⓒ \(3\sqrt{3}i\)
Now that we are familiar with the imaginary number i, we can expand our concept of the number system to include imaginary numbers. The complex number system includes the real numbers and the imaginary numbers. A complex number is of the form a + bi, where a, b are real numbers. We call a the real part and b the imaginary part.
A complex number is of the form a + bi, where a and b are real numbers.
A complex number is in standard form when written as \(a+bi,\) where a and b are real numbers.
If \(b=0,\) then \(a+bi\) becomes \(a+0·i=a,\) and is a real number.
If \(b\ne 0,\) then \(a+bi\) is an imaginary number.
If \(a=0,\) then \(a+bi\) becomes \(0+bi=bi,\) and is called a pure imaginary number.
We summarize this here.
| \(a+bi\) | ||
| \(b=0\) | \(\begin{array}{l} \\ a+0·i \\ \\ \,a\end{array}\) | Real number |
| \(b\ne 0\) | \(a+bi\) | Imaginary number |
| \(a=0\) | \(\begin{array}{l}0+bi \\ \\ \\ \,bi\end{array}\) | Pure imaginary number |
The standard form of a complex number is \(a+bi,\) so this explains why the preferred form is \(\sqrt{\text{-}b}=\sqrt{b}i\) when \(b>0.\)
The diagram helps us visualize the complex number system. It is made up of both the real numbers and the imaginary numbers.
Add or Subtract Complex Numbers
We are now ready to perform the operations of addition, subtraction, multiplication and division on the complex numbers—just as we did with the real numbers.
Adding and subtracting complex numbers is much like adding or subtracting like terms. We add or subtract the real parts and then add or subtract the imaginary parts. Our final result should be in standard form.
Add: \(\sqrt{-12}+\sqrt{-27}.\)
Rewrite each square root as a complex number first, then combine the like imaginary terms.
| \(\sqrt{-12}+\sqrt{-27}\) | |
| Use the definition of the square root of negative numbers. | \(\sqrt{12}\,i+\sqrt{27}\,i\) |
| Simplify the square roots. | \(2\sqrt{3}\,i+3\sqrt{3}\,i\) |
| Add. | \(5\sqrt{3}\,i\) |
Add: \(\sqrt{-8}+\sqrt{-32}.\)
\(6\sqrt{2}i\)
Add: \(\sqrt{-27}+\sqrt{-48}.\)
\(7\sqrt{3}i\)
Remember to add both the real parts and the imaginary parts in this next example.
Simplify: ⓐ \((4-3i)+(5+6i)\) ⓑ \((2-5i)-(5-2i).\)
Group the real parts together and the imaginary parts together, then combine each.
ⓐ
ⓑ
| \((4-3i)+(5+6i)\) | |
| Use the Associative Property to put the real parts and the imaginary parts together. | \((4+5)+(-3i+6i)\) |
| Simplify. | \(9+3i\) |
| \((2-5i)-(5-2i)\) | |
| Distribute. | \(2-5i-5+2i\) |
| Use the Associative Property to put the real parts and the imaginary parts together. | \(2-5-5i+2i\) |
| Simplify. | \(-3-3i\) |
Simplify: ⓐ \((2+7i)+(4-2i)\) ⓑ \((8-4i)-(2-i).\)
ⓐ \(6+5i\) ⓑ \(6-3i\)
Simplify: ⓐ \((3-2i)+(-5-4i)\) ⓑ \((4+3i)-(2-6i).\)
ⓐ \(-2-6i\) ⓑ \(2+9i\)
Multiply Complex Numbers
Multiplying complex numbers is also much like multiplying expressions with coefficients and variables. There is only one special case we need to consider. We will look at that after we practice in the next two examples.
Multiply: \(2i(7-5i).\)
Distribute \(2i\) across the parentheses, then replace \({i}^{2}\) with \(-1.\)
| \(2i(7-5i)\) | |
| Distribute. | \(14i-10{i}^{2}\) |
| Simplify \({i}^{2}.\) | \(14i-10(-1)\) |
| Multiply. | \(14i+10\) |
| Write in standard form. | \(10+14i\) |
Multiply: \(4i(5-3i).\)
\(12+20i\)
Multiply: \(-3i(2+4i).\)
\(12-6i\)
In the next example, we multiply the binomials using the Distributive Property or FOIL.
Multiply: \((3+2i)(4-3i).\)
Use FOIL to multiply the two binomials, then replace \({i}^{2}\) with \(-1.\)
| \((3+2i)(4-3i)\) | |
| Use FOIL. | \(12-9i+8i-6{i}^{2}\) |
| Simplify \({i}^{2}\) and combine like terms. | \(12-i-6(-1)\) |
| Multiply. | \(12-i+6\) |
| Combine the real parts. | \(18-i\) |
Multiply: \((5-3i)(-1-2i).\)
\(-11-7i\)
Multiply: \((-4-3i)(2+i).\)
\(-5-10i\)
In the next example, we could use FOIL or the Product of Binomial Squares Pattern.
Multiply: \({(3+2i)}^{2}\)
Apply the binomial squares pattern \({(a+b)}^{2}={a}^{2}+2ab+{b}^{2},\) then simplify \({i}^{2}.\)
| |
| Use the Product of Binomial Squares Pattern, \({(a+b)}^{2}={a}^{2}+2ab+{b}^{2}.\) |
|
| Simplify. |
|
| Simplify \({i}^{2}.\) |
|
| Simplify. |
|
Multiply using the Binomial Squares pattern: \({(-2-5i)}^{2}.\)
\(-21+20i\)
Multiply using the Binomial Squares pattern: \({(-5+4i)}^{2}.\)
\(9-40i\)
Since the square root of a negative number is not a real number, when we have the square roots of two negative numbers, we cannot use the Product Property for Radicals. In order to multiply square roots of negative numbers we should first write them as complex numbers, using \(\sqrt{\text{-}b}=\sqrt{b}i.\) This is one place students tend to make errors, so be careful when you see multiplying with a negative square root.
Multiply: \(\sqrt{-36}·\sqrt{-4}.\)
Rewrite each square root as a complex number before multiplying — never multiply the negative radicands directly.
To multiply square roots of negative numbers, we first write them as complex numbers.
| \(\sqrt{-36}·\sqrt{-4}\) | |
| Write as complex numbers using \(\sqrt{\text{-}b}=\sqrt{b}i.\) | \(\sqrt{36}\,i·\sqrt{4}\,i\) |
| Simplify. | \(6i·2i\) |
| Multiply. | \(12{i}^{2}\) |
| Simplify \({i}^{2}\) and multiply. | \(-12\) |
Multiply: \(\sqrt{-49}·\sqrt{-4}.\)
\(-14\)
Multiply: \(\sqrt{-36}·\sqrt{-81}.\)
\(-54\)
In the next example, each binomial has a square root of a negative number. Before multiplying, each square root of a negative number must be written as a complex number.
Multiply: \((3-\sqrt{-12})(5+\sqrt{-27}).\)
Rewrite each square root as a complex number first, then use FOIL to multiply the binomials.
To multiply square roots of negative numbers, we first write them as complex numbers.
| \((3-\sqrt{-12})(5+\sqrt{-27})\) | |
| Write as complex numbers using \(\sqrt{\text{-}b}=\sqrt{b}i.\) | \((3-2\sqrt{3}\,i)(5+3\sqrt{3}\,i)\) |
| Use FOIL. | \(15+9\sqrt{3}\,i-10\sqrt{3}\,i-6·3{i}^{2}\) |
| Combine like terms and simplify \({i}^{2}.\) | \(15-\sqrt{3}\,i-6·(-3)\) |
| Multiply and combine like terms. | \(33-\sqrt{3}\,i\) |
Multiply: \((4-\sqrt{-12})(3-\sqrt{-48}).\)
\(-12-22\sqrt{3}i\)
Multiply: \((-2+\sqrt{-8})(3-\sqrt{-18}).\)
\(6+12\sqrt{2}i\)
We first looked at conjugate pairs when we studied polynomials. We said that a pair of binomials that each have the same first term and the same last term, but one is a sum and one is a difference is called a conjugate pair and is of the form \((a-b),(a+b).\)
A complex conjugate pair is very similar. For a complex number of the form \(a+bi,\) its conjugate is \(a-bi.\) Notice they have the same first term and the same last term, but one is a sum and one is a difference.
A complex conjugate pair is of the form \(a+bi,\) \(a-bi.\)
We will multiply a complex conjugate pair in the next example.
Multiply: \((3-2i)(3+2i).\)
Use FOIL to multiply the conjugate pair, then simplify \({i}^{2}.\)
| \((3-2i)(3+2i)\) | |
| Use FOIL. | \(9+6i-6i-4{i}^{2}\) |
| Combine like terms and simplify \({i}^{2}.\) | \(9-4(-1)\) |
| Multiply and combine like terms. | 13 |
Multiply: \((4-3i)·(4+3i).\)
25
Multiply: \((-2+5i)·(-2-5i).\)
29
From our study of polynomials, we know the product of conjugates is always of the form \((a-b)(a+b)={a}^{2}-{b}^{2}.\) The result is called a difference of squares. We can multiply a complex conjugate pair using this pattern.
The last example we used FOIL. Now we will use the Product of Conjugates Pattern.
Notice this is the same result we found in Example 9.
When we multiply complex conjugates, the product of the last terms will always have an \({i}^{2}\) which simplifies to \(-1.\)
\[\begin{array}{l}(a-bi)(a+bi) \\ {a}^{2}-{(bi)}^{2} \\ {a}^{2}-{b}^{2}{i}^{2} \\ {a}^{2}-{b}^{2}(-1) \\ {a}^{2}+{b}^{2}\end{array}\]
This leads us to the Product of Complex Conjugates Pattern: \((a-bi)(a+bi)={a}^{2}+{b}^{2}\)
If a and b are real numbers, then
\[(a-bi)(a+bi)={a}^{2}+{b}^{2}\]
Multiply using the Product of Complex Conjugates Pattern: \((8-2i)(8+2i).\)
Apply the pattern \((a-bi)(a+bi)={a}^{2}+{b}^{2}\) directly.
| |
| Use the Product of Complex Conjugates Pattern, \((a-bi)(a+bi)={a}^{2}+{b}^{2}.\) |
|
| Simplify the squares. |
|
| Add. |
|
Multiply using the Product of Complex Conjugates Pattern: \((3-10i)(3+10i).\)
109
Multiply using the Product of Complex Conjugates Pattern: \((-5+4i)(-5-4i).\)
41
Divide Complex Numbers
Dividing complex numbers is much like rationalizing a denominator. We want our result to be in standard form with no imaginary numbers in the denominator.
Divide: \(\frac{4+3i}{3-4i}.\)
Multiply the numerator and denominator by the complex conjugate of the denominator.
Divide: \(\frac{2+5i}{5-2i}.\)
i
Divide: \(\frac{1+6i}{6-i}.\)
i
We summarize the steps here.
- Write both the numerator and denominator in standard form.
- Multiply the numerator and denominator by the complex conjugate of the denominator.
- Simplify and write the result in standard form.
Divide, writing the answer in standard form: \(\frac{-3}{5+2i}.\)
Multiply the numerator and denominator by the conjugate of the denominator, \(5-2i.\)
| \(\frac{-3}{5+2i}\) | |
| Multiply the numerator and denominator by the complex conjugate of the denominator. | \(\frac{-3(5-2i)}{(5+2i)(5-2i)}\) |
| Multiply in the numerator and use the Product of Complex Conjugates Pattern in the denominator. | \(\frac{-15+6i}{{5}^{2}+{2}^{2}}\) |
| Simplify. | \(\frac{-15+6i}{29}\) |
| Write in standard form. | \(-\frac{15}{29}+\frac{6}{29}i\) |
Divide, writing the answer in standard form: \(\frac{4}{1-4i}.\)
\(\frac{4}{17}+\frac{16}{17}i\)
Divide, writing the answer in standard form: \(\frac{-2}{-1+2i}.\)
\(\frac{2}{5}+\frac{4}{5}i\)
Be careful as you find the conjugate of the denominator.
Divide: \(\frac{5+3i}{4i}.\)
Write the denominator in standard form as \(0+4i\) first, then multiply by its conjugate.
| \(\frac{5+3i}{4i}\) | |
| Write the denominator in standard form. | \(\frac{5+3i}{0+4i}\) |
| Multiply the numerator and denominator by the complex conjugate of the denominator. | \(\frac{(5+3i)(0-4i)}{(0+4i)(0-4i)}\) |
| Simplify. | \(\frac{(5+3i)(-4i)}{(4i)(-4i)}\) |
| Multiply. | \(\frac{-20i-12{i}^{2}}{-16{i}^{2}}\) |
| Simplify the \({i}^{2}.\) | \(\frac{-20i+12}{16}\) |
| Rewrite in standard form. | \(\,\frac{12}{16}-\frac{20}{16}i\) |
| Simplify the fractions. | \(\,\frac{3}{4}-\frac{5}{4}i\) |
Divide: \(\frac{3+3i}{2i}.\)
\(\frac{3}{2}-\frac{3}{2}i\)
Divide: \(\frac{2+4i}{5i}.\)
\(\frac{4}{5}-\frac{2}{5}i\)
Simplify Powers of i
The powers of \(i\) make an interesting pattern that will help us simplify higher powers of i. Let’s evaluate the powers of \(i\) to see the pattern.
\[\begin{array}{llllllllll}{i}^{1} & & & \,{i}^{2} & & & \,{i}^{3} & & & \,{i}^{4} \\ i & & & \,-1 & & & \,{i}^{2}·i & & & \,{i}^{2}·{i}^{2} \\ & & & & & & \,-1·i & & & \,(-1)(-1) \\ & & & & & & \,-i & & & \,1 \\ \\ \\ {i}^{5} & & & \,{i}^{6} & & & \,{i}^{7} & & & \,{i}^{8} \\ {i}^{4}·i & & & \,{i}^{4}·{i}^{2} & & & \,{i}^{4}·{i}^{3} & & & \,{i}^{4}·{i}^{4} \\ 1·i & & & \,1·{i}^{2} & & & \,1·{i}^{3} & & & \,1·1 \\ i & & & \,{i}^{2} & & & \,{i}^{3} & & & \,1 \\ & & & \,-1 & & & \,-i\end{array}\]
We summarize this now.
\[\begin{array}{llllllll}{i}^{1} & = & i & & & \,{i}^{5} & = & i \\ {i}^{2} & = & -1 & & & \,{i}^{6} & = & -1 \\ {i}^{3} & = & \text{-}i & & & \,{i}^{7} & = & \text{-}i \\ {i}^{4} & = & 1 & & & \,{i}^{8} & = & 1\end{array}\]
If we continued, the pattern would keep repeating in blocks of four. We can use this pattern to help us simplify powers of i. Since i4 = 1, we rewrite each power, in, as a product using i4 to a power and another power of i.
We rewrite it in the form \({i}^{n}={({i}^{4})}^{q}·{i}^{r},\) where the exponent, q, is the quotient of n divided by 4 and the exponent, r, is the remainder from this division. For example, to simplify i57, we divide 57 by 4 and we get 14 with a remainder of 1. In other words, \(57=4·14+1.\) So we write \({i}^{57}={({1}^{4})}^{14}·{i}^{1}\) and then simplify from there.
Simplify: \({i}^{86}.\)
Divide the exponent by 4 and rewrite \({i}^{86}\) as \({({i}^{4})}^{q}·{i}^{r}\) using the quotient and remainder.
| \({i}^{86}\) | |
| Divide 86 by 4 and rewrite \({i}^{86}\) in the \({i}^{n}={({i}^{4})}^{q}·{i}^{r}\) form. | \({({1}^{4})}^{21}·{i}^{2}\) |
| |
| Simplify. | \({(1)}^{21}·(-1)\) |
| Simplify. | \(-1\) |
Simplify: \({i}^{75}.\)
\(\text{-}i\)
Simplify: \({i}^{92}.\)
\(1\)
Access these online resources for additional instruction and practice with the complex number system.
Key Concepts
- Square Root of a Negative Number
- If b is a positive real number, then \(\sqrt{\text{-}b}=\sqrt{b}i\)
Table 18 \(a+bi\) \(b=0\) \(\begin{array}{l} \\ a+0·i \\ \\ \,a\end{array}\) Real number \(b\ne 0\) \(a+bi\) Imaginary number \(a=0\) \(\begin{array}{l}0+bi \\ \\ \\ \,bi\end{array}\) Pure imaginary number - A complex number is in standard form when written as a + bi, where a, b are real numbers.
- If b is a positive real number, then \(\sqrt{\text{-}b}=\sqrt{b}i\)
- Product of Complex Conjugates
- If a, b are real numbers, then
\((a-bi)(a+bi)={a}^{2}+{b}^{2}\)
- If a, b are real numbers, then
- How to Divide Complex Numbers
- Write both the numerator and denominator in standard form.
- Multiply the numerator and denominator by the complex conjugate of the denominator.
- Simplify and write the result in standard form.
Section Exercises
Practice Makes Perfect
Evaluate the Square Root of a Negative Number
In the following exercises, write each expression in terms of i and simplify if possible.
ⓐ \(\sqrt{-16}\) ⓑ \(\sqrt{-11}\)
ⓒ \(\sqrt{-8}\)
ⓐ \(4i\) ⓑ \(\sqrt{11}i\) ⓒ \(2\sqrt{2}i\)
ⓐ \(\sqrt{-121}\) ⓑ \(\sqrt{-1}\) ⓒ \(\sqrt{-20}\)
ⓐ \(\sqrt{-100}\) ⓑ \(\sqrt{-13}\) ⓒ \(\sqrt{-45}\)
ⓐ \(10i\) ⓑ \(\sqrt{13}i\) ⓒ \(3\sqrt{5}i\)
ⓐ \(\sqrt{-49}\) ⓑ \(\sqrt{-15}\) ⓒ \(\sqrt{-75}\)
Add or Subtract Complex Numbers In the following exercises, add or subtract.
\(\sqrt{-75}+\sqrt{-48}\)
\(9\sqrt{3}i\)
\(\sqrt{-12}+\sqrt{-75}\)
\(\sqrt{-50}+\sqrt{-18}\)
\(8\sqrt{2}i\)
\(\sqrt{-72}+\sqrt{-8}\)
\((1+3i)+(7+4i)\)
\(8+7i\)
\((6+2i)+(3-4i)\)
\((8-i)+(6+3i)\)
\(14+2i\)
\((7-4i)+(-2-6i)\)
\((1-4i)-(3-6i)\)
\(-2+2i\)
\((8-4i)-(3+7i)\)
\((6+i)-(-2-4i)\)
\(8+5i\)
\((-2+5i)-(-5+6i)\)
\((5-\sqrt{-36})+(2-\sqrt{-49})\)
\(7-13i\)
\((-3+\sqrt{-64})+(5-\sqrt{-16})\)
\((-7-\sqrt{-50})-(-32-\sqrt{-18})\)
\(25-2\sqrt{2}i\)
\((-5+\sqrt{-27})-(-4-\sqrt{-48})\)
Multiply Complex Numbers
In the following exercises, multiply.
\(4i(5-3i)\)
\(12+20i\)
\(2i(-3+4i)\)
\(-6i(-3-2i)\)
\(-12+18i\)
\(\text{-}i(6+5i)\)
\((4+3i)(-5+6i)\)
\(-38++9i\)
\((-2-5i)(-4+3i)\)
\((-3+3i)(-2-7i)\)
\(27+15i\)
\((-6-2i)(-3-5i)\)
In the following exercises, multiply using the Product of Binomial Squares Pattern.
\({(3+4i)}^{2}\)
\(-7+24i\)
\({(-1+5i)}^{2}\)
\({(-2-3i)}^{2}\)
\(-5+12i\)
\({(-6-5i)}^{2}\)
In the following exercises, multiply.
\(\sqrt{-25}·\sqrt{-36}\)
\(-30\)
\(\sqrt{-4}·\sqrt{-16}\)
\(\sqrt{-9}·\sqrt{-100}\)
\(-30\)
\(\sqrt{-64}·\sqrt{-9}\)
\((-2-\sqrt{-27})(4-\sqrt{-48})\)
\(-44-4i\sqrt{3}\)
\((5-\sqrt{-12})(-3+\sqrt{-75})\)
\((2+\sqrt{-8})(-4+\sqrt{-18})\)
\(-20-2\sqrt{2}i\)
\((5+\sqrt{-18})(-2-\sqrt{-50})\)
\((2-i)(2+i)\)
5
\((4-5i)(4+5i)\)
\((7-2i)(7+2i)\)
53
\((-3-8i)(-3+8i)\)
In the following exercises, multiply using the Product of Complex Conjugates Pattern.
\((7-i)(7+i)\)
50
\((6-5i)(6+5i)\)
\((9-2i)(9+2i)\)
85
\((-3-4i)(-3+4i)\)
Divide Complex Numbers
In the following exercises, divide.
\(\frac{3+4i}{4-3i}\)
i
\(\frac{5-2i}{2+5i}\)
\(\frac{2+i}{3-4i}\)
\(\frac{2}{25}+\frac{11}{25}i\)
\(\frac{3-2i}{6+i}\)
\(\frac{3}{2-3i}\)
\(\frac{6}{13}+\frac{9}{13}i\)
\(\frac{2}{4-5i}\)
\(\frac{-4}{3-2i}\)
\(-\frac{12}{13}-\frac{8}{13}i\)
\(\frac{-1}{3+2i}\)
\(\frac{1+4i}{3i}\)
\(\frac{4}{3}-\frac{1}{3}i\)
\(\frac{4+3i}{7i}\)
\(\frac{-2-3i}{4i}\)
\(-\frac{3}{4}+\frac{1}{2}i\)
\(\frac{-3-5i}{2i}\)
Simplify Powers of i
In the following exercises, simplify.
\({i}^{41}\)
i
\({i}^{39}\)
\({i}^{66}\)
\(-1\)
\({i}^{48}\)
\({i}^{128}\)
1
\({i}^{162}\)
\({i}^{137}\)
i
\({i}^{255}\)
Writing Exercises
Explain the relationship between real numbers and complex numbers.
Answers will vary.
Aniket multiplied as follows and he got the wrong answer. What is wrong with his reasoning?
\(\begin{array}{l}\sqrt{-7}·\sqrt{-7} \\ \sqrt{49} \\ 7\end{array}\)
Why is \(\sqrt{-64}=8i\) but \(\sqrt[3]{-64}=-4.\)
Answers will vary.
Explain how dividing complex numbers is similar to rationalizing a denominator.
Self Check
ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.
ⓑ On a scale of \(1-10,\) how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?
Chapter Review Exercises
Simplify Expressions with Roots
Simplify Expressions with Roots
In the following exercises, simplify.
ⓐ \(\sqrt{225}\) ⓑ \(\text{-}\sqrt{16}\)
ⓐ 15 ⓑ \(-4\)
ⓐ \(\text{-}\sqrt{169}\) ⓑ \(\sqrt{-8}\)
ⓐ \(\sqrt[3]{8}\) ⓑ \(\sqrt[4]{81}\) ⓒ \(\sqrt[5]{243}\)
ⓐ 2 ⓑ 3 ⓒ 3
ⓐ \(\sqrt[3]{-512}\) ⓑ \(\sqrt[4]{-81}\) ⓒ \(\sqrt[5]{-1}\)
Estimate and Approximate Roots
In the following exercises, estimate each root between two consecutive whole numbers.
ⓐ \(\sqrt{68}\) ⓑ \(\sqrt[3]{84}\)
ⓐ \(8<\sqrt{68}<9\)
ⓑ \(4<\sqrt[3]{84}<5\)
In the following exercises, approximate each root and round to two decimal places.
ⓐ \(\sqrt{37}\) ⓑ \(\sqrt[3]{84}\) ⓒ \(\sqrt[4]{125}\)
Simplify Variable Expressions with Roots
In the following exercises, simplify using absolute values as necessary.
ⓐ \(\sqrt[3]{{a}^{3}}\)
ⓑ \(\sqrt[7]{{b}^{7}}\)
ⓐ a ⓑ \(b\)
ⓐ \(\sqrt{{a}^{14}}\)
ⓑ \(\sqrt{{w}^{24}}\)
ⓐ \(\sqrt[4]{{m}^{8}}\)
ⓑ \(\sqrt[5]{{n}^{20}}\)
ⓐ \({m}^{2}\) ⓑ \({n}^{4}\)
ⓐ \(\sqrt{121{m}^{20}}\)
ⓑ \(\text{-}\sqrt{64{a}^{2}}\)
ⓐ \(\sqrt[3]{216{a}^{6}}\)
ⓑ \(\sqrt[5]{32{b}^{20}}\)
ⓐ \(6{a}^{2}\) ⓑ \(2{b}^{4}\)
ⓐ \(\sqrt{144{x}^{2}{y}^{2}}\)
ⓑ \(\sqrt{169{w}^{8}{y}^{10}}\)
ⓒ \(\sqrt[3]{8{a}^{51}{b}^{6}}\)
Simplify Radical Expressions
Use the Product Property to Simplify Radical Expressions
In the following exercises, use the Product Property to simplify radical expressions.
\(\sqrt{125}\)
\(5\sqrt{5}\)
\(\sqrt{675}\)
ⓐ \(\sqrt[3]{625}\) ⓑ \(\sqrt[6]{128}\)
ⓐ \(5\sqrt[3]{5}\) ⓑ \(2\sqrt[6]{2}\)
In the following exercises, simplify using absolute value signs as needed.
ⓐ \(\sqrt{{a}^{23}}\)
ⓑ \(\sqrt[3]{{b}^{8}}\)
ⓒ \(\sqrt[8]{{c}^{13}}\)
ⓐ \(\sqrt{80{s}^{15}}\)
ⓑ \(\sqrt[5]{96{a}^{7}}\)
ⓒ \(\sqrt[6]{128{b}^{7}}\)
ⓐ \(4|{s}^{7}|\sqrt[]{5s}\) ⓑ \(2a\sqrt[5]{3{a}^{2}}\)
ⓒ \(2|b|\sqrt[6]{2b}\)
ⓐ \(\sqrt{96{r}^{3}{s}^{3}}\)
ⓑ \(\sqrt[3]{80{x}^{7}{y}^{6}}\)
ⓒ \(\sqrt[4]{80{x}^{8}{y}^{9}}\)
ⓐ \(\sqrt[5]{-32}\)
ⓑ \(\sqrt[8]{-1}\)
ⓐ \(-2\) ⓑ not real
ⓐ \(8+\sqrt{96}\)
ⓑ \(\frac{2+\sqrt{40}}{2}\)
Use the Quotient Property to Simplify Radical Expressions
In the following exercises, use the Quotient Property to simplify square roots.
ⓐ \(\sqrt{\frac{72}{98}}\) ⓑ \(\sqrt[3]{\frac{24}{81}}\) ⓒ \(\sqrt[4]{\frac{6}{96}}\)
ⓐ \(\frac{6}{7}\) ⓑ \(\frac{2}{3}\) ⓒ \(\frac{1}{2}\)
ⓐ \(\sqrt{\frac{{y}^{4}}{{y}^{8}}}\) ⓑ \(\sqrt[5]{\frac{{u}^{21}}{{u}^{11}}}\) ⓒ \(\sqrt[6]{\frac{{v}^{30}}{{v}^{12}}}\)
\(\sqrt{\frac{300{m}^{5}}{64}}\)
\(\frac{5{m}^{2}\sqrt{3m}}{4}\)
ⓐ \(\sqrt{\frac{28{p}^{7}}{{q}^{2}}}\)
ⓑ \(\sqrt[3]{\frac{81{s}^{8}}{{t}^{3}}}\)
ⓒ \(\sqrt[4]{\frac{64{p}^{15}}{{q}^{12}}}\)
ⓐ \(\sqrt{\frac{27{p}^{2}q}{108{p}^{4}{q}^{3}}}\)
ⓑ \(\sqrt[3]{\frac{16{c}^{5}{d}^{7}}{250{c}^{2}{d}^{2}}}\)
ⓒ \(\sqrt[6]{\frac{2{m}^{9}{n}^{7}}{128{m}^{3}n}}\)
ⓐ \(\frac{1}{2|pq|}\) ⓑ \(\frac{2cd}{5}\sqrt[3]{{d}^{2}}\)
ⓒ \(\frac{|mn|}{2}\)
ⓐ \(\frac{\sqrt{80{q}^{5}}}{\sqrt{5q}}\)
ⓑ \(\frac{\sqrt[3]{-625}}{\sqrt[3]{5}}\)
ⓒ \(\frac{\sqrt[4]{80{m}^{7}}}{\sqrt[4]{5m}}\)
Simplify Rational Exponents
Simplify expressions with \({a}^{\frac{1}{n}}\)
In the following exercises, write as a radical expression.
ⓐ \({r}^{\frac{1}{2}}\) ⓑ \({s}^{\frac{1}{3}}\) ⓒ \({t}^{\frac{1}{4}}\)
ⓐ \(\sqrt{r}\) ⓑ \(\sqrt[3]{s}\) ⓒ \(\sqrt[4]{t}\)
In the following exercises, write with a rational exponent.
ⓐ \(\sqrt{21p}\) ⓑ \(\sqrt[4]{8q}\) ⓒ \(4\sqrt[6]{36r}\)
In the following exercises, simplify.
ⓐ \({625}^{\frac{1}{4}}\)
ⓑ \({243}^{\frac{1}{5}}\)
ⓒ \({32}^{\frac{1}{5}}\)
ⓐ 5 ⓑ 3 ⓒ 2
ⓐ \({(-1,000)}^{\frac{1}{3}}\)
ⓑ \(\text{-}{1,000}^{\frac{1}{3}}\)
ⓒ \({(1,000)}^{-\frac{1}{3}}\)
ⓐ \({(-32)}^{\frac{1}{5}}\)
ⓑ \({(243)}^{-\frac{1}{5}}\)
ⓒ \(\text{-}{125}^{\frac{1}{3}}\)
ⓐ \(-2\) ⓑ \(\frac{1}{3}\) ⓒ \(-5\)
Simplify Expressions with \({a}^{\frac{m}{n}}\)
In the following exercises, write with a rational exponent.
ⓐ \(\sqrt[4]{{r}^{7}}\)
ⓑ \({(\sqrt[5]{2pq})}^{3}\)
ⓒ \(\sqrt[4]{{(\frac{12m}{7n})}^{3}}\)
In the following exercises, simplify.
ⓐ \({25}^{\frac{3}{2}}\)
ⓑ \({9}^{-\frac{3}{2}}\)
ⓒ \({(-64)}^{\frac{2}{3}}\)
ⓐ 125 ⓑ \(\frac{1}{27}\) ⓒ 16
ⓐ \(\text{-}{64}^{\frac{3}{2}}\)
ⓑ \(\text{-}{64}^{-\frac{3}{2}}\)
ⓒ \({(-64)}^{\frac{3}{2}}\)
Use the Laws of Exponents to Simplify Expressions with Rational Exponents
In the following exercises, simplify.
ⓐ \({6}^{\frac{5}{2}}·{6}^{\frac{1}{2}}\)
ⓑ \({({b}^{15})}^{\frac{3}{5}}\)
ⓒ \(\frac{{w}^{\frac{2}{7}}}{{w}^{\frac{9}{7}}}\)
ⓐ \({6}^{3}\) ⓑ \({b}^{9}\) ⓒ \(\frac{1}{w}\)
ⓐ \(\frac{{a}^{\frac{3}{4}}·{a}^{-\frac{1}{4}}}{{a}^{-\frac{10}{4}}}\)
ⓑ \({(\frac{27\,{b}^{\frac{2}{3}}\,{c}^{-\frac{5}{2}}}{{b}^{-\frac{7}{3}}{c}^{\frac{1}{2}}})}^{\frac{1}{3}}\)
Add, Subtract and Multiply Radical Expressions
Add and Subtract Radical Expressions
In the following exercises, simplify.
ⓐ \(7\sqrt{2}-3\sqrt{2}\)
ⓑ \(7\sqrt[3]{p}+2\sqrt[3]{p}\)
ⓒ \(5\sqrt[3]{x}-3\sqrt[3]{x}\)
ⓐ \(4\sqrt{2}\) ⓑ \(9\sqrt[3]{p}\) ⓒ \(2\sqrt[3]{x}\)
ⓐ \(\sqrt{11b}-5\sqrt{11b}+3\sqrt{11b}\)
ⓑ \(8\sqrt[4]{11cd}+5\sqrt[4]{11cd}-9\sqrt[4]{11cd}\)
ⓐ \(\sqrt{48}+\sqrt{27}\)
ⓑ \(\sqrt[3]{54}+\sqrt[3]{128}\)
ⓒ \(6\sqrt[4]{5}-\frac{3}{2}\sqrt[4]{80}\)
ⓐ \(7\sqrt{3}\) ⓑ \(7\sqrt[3]{2}\) ⓒ \(3\sqrt[4]{5}\)
ⓐ \(\sqrt{80{c}^{7}}-\sqrt{20{c}^{7}}\)
ⓑ \(2\sqrt[4]{162{r}^{10}}+4\sqrt[4]{32{r}^{10}}\)
\(3\sqrt{75{y}^{2}}+8y\sqrt{48}-\sqrt{300{y}^{2}}\)
\(37y\sqrt{3}\)
Multiply Radical Expressions
In the following exercises, simplify.
ⓐ \((5\sqrt{6})(\text{-}\sqrt{12})\)
ⓑ \((-2\sqrt[4]{18})(\text{-}\sqrt[4]{9})\)
ⓐ \((3\sqrt{2{x}^{3}})(7\sqrt{18{x}^{2}})\)
ⓑ \((-6\sqrt[3]{20{a}^{2}})(-2\sqrt[3]{16{a}^{3}})\)
ⓐ \(126{x}^{2}\sqrt{x}\) ⓑ \(48a\sqrt[3]{5{a}^{2}}\)
Use Polynomial Multiplication to Multiply Radical Expressions
In the following exercises, multiply.
ⓐ \(\sqrt{11}(8+4\sqrt{11})\)
ⓑ \(\sqrt[3]{3}(\sqrt[3]{9}+\sqrt[3]{18})\)
ⓐ \((3-2\sqrt{7})(5-4\sqrt{7})\)
ⓑ \((\sqrt[3]{x}-5)(\sqrt[3]{x}-3)\)
ⓐ \(71-22\sqrt{7}\)
ⓑ \(\sqrt[3]{{x}^{2}}-8\sqrt[3]{x}+15\)
\((2\sqrt{7}-5\sqrt{11})(4\sqrt{7}+9\sqrt{11})\)
ⓐ \({(4+\sqrt{11})}^{2}\)
ⓑ \({(3-2\sqrt{5})}^{2}\)
ⓐ \(27+8\sqrt{11}\) ⓑ \(29-12\sqrt{5}\)
\((7+\sqrt{10})(7-\sqrt{10})\)
\((\sqrt[3]{3x}+2)(\sqrt[3]{3x}-2)\)
\(\sqrt[3]{9{x}^{2}}-4\)
Divide Radical Expressions
Divide Square Roots
In the following exercises, simplify.
ⓐ \(\frac{\sqrt{48}}{\sqrt{75}}\)
ⓑ \(\frac{\sqrt[3]{81}}{\sqrt[3]{24}}\)
ⓐ \(\frac{\sqrt{320m{n}^{-5}}}{\sqrt{45{m}^{-7}{n}^{3}}}\)
ⓑ \(\frac{\sqrt[3]{16{x}^{4}{y}^{-2}}}{\sqrt[3]{-54{x}^{-2}{y}^{4}}}\)
ⓐ \(\frac{8{m}^{4}}{3{n}^{4}}\) ⓑ \(-\frac{2{x}^{2}}{3{y}^{2}}\)
Rationalize a One Term Denominator
In the following exercises, rationalize the denominator.
ⓐ \(\frac{8}{\sqrt{3}}\) ⓑ \(\sqrt{\frac{7}{40}}\) ⓒ \(\frac{8}{\sqrt{2y}}\)
ⓐ \(\frac{1}{\sqrt[3]{11}}\) ⓑ \(\sqrt[3]{\frac{7}{54}}\) ⓒ \(\frac{3}{\sqrt[3]{3{x}^{2}}}\)
ⓐ \(\frac{\sqrt[3]{121}}{11}\) ⓑ \(\frac{\sqrt[3]{28}}{6}\) ⓒ \(\frac{\sqrt[3]{9x}}{x}\)
ⓐ \(\frac{1}{\sqrt[4]{4}}\) ⓑ \(\sqrt[4]{\frac{9}{32}}\) ⓒ \(\frac{6}{\sqrt[4]{9{x}^{3}}}\)
Rationalize a Two Term Denominator
In the following exercises, simplify.
\(\frac{7}{2-\sqrt{6}}\)
\(-\frac{7(2+\sqrt{6})}{2}\)
\(\frac{\sqrt{5}}{\sqrt{n}-\sqrt{7}}\)
\(\frac{\sqrt{x}+\sqrt{8}}{\sqrt{x}-\sqrt{8}}\)
\({\frac{(\sqrt{x}+2\sqrt{2})}{x-8}}^{2}\)
Solve Radical Equations
Solve Radical Equations
In the following exercises, solve.
\(\sqrt{4x-3}=7\)
\(\sqrt{5x+1}=-3\)
no solution
\(\sqrt[3]{4x-1}=3\)
\(\sqrt{u-3}+3=u\)
\(u=3,u=4\)
\(\sqrt[3]{4x+5}-2=-5\)
\({(8x+5)}^{\frac{1}{3}}+2=-1\)
\(x=-4\)
\(\sqrt{y+4}-y+2=0\)
\(2\sqrt{8r+1}-8=2\)
\(r=3\)
Solve Radical Equations with Two Radicals
In the following exercises, solve.
\(\sqrt{10+2c}=\sqrt{4c+16}\)
\(\sqrt[3]{2{x}^{2}+9x-18}=\sqrt[3]{{x}^{2}+3x-2}\)
\(x=-8,x=2\)
\(\sqrt{r}+6=\sqrt{r+8}\)
\(\sqrt{x+1}-\sqrt{x-2}=1\)
\(x=3\)
Use Radicals in Applications
In the following exercises, solve. Round approximations to one decimal place.
Landscaping Reed wants to have a square garden plot in his backyard. He has enough compost to cover an area of 75 square feet. Use the formula \(s=\sqrt{A}\) to find the length of each side of his garden. Round your answer to the nearest tenth of a foot.
Accident investigation An accident investigator measured the skid marks of one of the vehicles involved in an accident. The length of the skid marks was 175 feet. Use the formula \(s=\sqrt{24d}\) to find the speed of the vehicle before the brakes were applied. Round your answer to the nearest tenth.
\(64.8\) feet
Use Radicals in Functions
Evaluate a Radical Function
In the following exercises, evaluate each function.
\(g(x)=\sqrt{6x+1},\) find
ⓐ \(g(4)\)
ⓑ \(g(8)\)
\(G(x)=\sqrt{5x-1},\) find
ⓐ \(G(5)\)
ⓑ \(G(2)\)
ⓐ \(G(5)=2\sqrt{6}\) ⓑ \(G(2)=3\)
\(h(x)=\sqrt[3]{{x}^{2}-4},\) find
ⓐ \(h(-2)\)
ⓑ \(h(6)\)
For the function
\(g(x)=\sqrt[4]{4-4x},\) find
ⓐ \(g(1)\)
ⓑ \(g(-3)\)
ⓐ \(g(1)=0\) ⓑ \(g(-3)=2\)
Find the Domain of a Radical Function
In the following exercises, find the domain of the function and write the domain in interval notation.
\(g(x)=\sqrt{2-3x}\)
\(F(x)=\sqrt{\frac{x+3}{x-2}}\)
\((2,\infty )\)
\(f(x)=\sqrt[3]{4{x}^{2}-16}\)
\(F(x)=\sqrt[4]{10-7x}\)
\(\left(-\infty ,\frac{10}{7}\right)\)
Graph Radical Functions
In the following exercises, ⓐ find the domain of the function ⓑ graph the function ⓒ use the graph to determine the range.
\(g(x)=\sqrt{x+4}\)
\(g(x)=2\sqrt{x}\)
ⓐ domain: \([0,\infty )\)
ⓑ
ⓒ range: \([0,\infty )\)
\(f(x)=\sqrt[3]{x-1}\)
\(f(x)=\sqrt[3]{x}+3\)
ⓐ domain: \((\text{-}\infty ,\infty )\)
ⓑ
ⓒ range: \((\text{-}\infty ,\infty )\)
Use the Complex Number System
Evaluate the Square Root of a Negative Number
In the following exercises, write each expression in terms of i and simplify if possible.
ⓐ \(\sqrt{-100}\)
ⓑ \(\sqrt{-13}\)
ⓒ \(\sqrt{-45}\)
Add or Subtract Complex Numbers
In the following exercises, add or subtract.
\(\sqrt{-50}+\sqrt{-18}\)
\(8\sqrt{2}i\)
\((8-i)+(6+3i)\)
\((6+i)-(-2-4i)\)
\(8+5i\)
\((-7-\sqrt{-50})-(-32-\sqrt{-18})\)
Multiply Complex Numbers
In the following exercises, multiply.
\((-2-5i)(-4+3i)\)
\(23+14i\)
\(-6i(-3-2i)\)
\(\sqrt{-4}·\sqrt{-16}\)
\(-8\)
\((5-\sqrt{-12})(-3+\sqrt{-75})\)
In the following exercises, multiply using the Product of Binomial Squares Pattern.
\({(-2-3i)}^{2}\)
\(-5+12i\)
In the following exercises, multiply using the Product of Complex Conjugates Pattern.
\((9-2i)(9+2i)\)
Divide Complex Numbers
In the following exercises, divide.
\(\frac{2+i}{3-4i}\)
\(\frac{2}{25}+\frac{11}{25}i\)
\(\frac{-4}{3-2i}\)
Simplify Powers of i
In the following exercises, simplify.
\({i}^{48}\)
1
\({i}^{255}\)
Practice Test
In the following exercises, simplify using absolute values as necessary.
\(\sqrt[3]{125{x}^{9}}\)
\(5{x}^{3}\)
\(\sqrt{169{x}^{8}{y}^{6}}\)
\(\sqrt[3]{72{x}^{8}{y}^{4}}\)
\(2{x}^{2}y\sqrt[3]{9{x}^{2}y}\)
\(\sqrt{\frac{45{x}^{3}{y}^{4}}{180{x}^{5}{y}^{2}}}\)
In the following exercises, simplify. Assume all variables are positive.
ⓐ \({256}^{-\frac{1}{4}}\) ⓑ \(\text{-}{49}^{\frac{3}{2}}\)
ⓐ \(\frac{1}{4}\) ⓑ \(-343\)
\(\sqrt{-45}\)
\(\frac{{x}^{-\frac{1}{4}}·{x}^{\frac{5}{4}}}{{x}^{-\frac{3}{4}}}\)
\({x}^{\frac{7}{4}}\)
\({(\frac{8\,{x}^{\frac{2}{3}}\,{y}^{-\frac{5}{2}}}{{x}^{-\frac{7}{3}}{y}^{\frac{1}{2}}})}^{\frac{1}{3}}\)
\(\sqrt{48{x}^{5}}-\sqrt{75{x}^{5}}\)
\(\text{-}{x}^{2}\sqrt{3x}\)
\(\sqrt{27{x}^{2}}-4x\sqrt{12}+\sqrt{108{x}^{2}}\)
\(2\sqrt{12{x}^{5}}·3\sqrt{6{x}^{3}}\)
\(36{x}^{4}\sqrt{2}\)
\(\sqrt[3]{4}(\sqrt[3]{16}-\sqrt[3]{6})\)
\((4-3\sqrt{3})(5+2\sqrt{3})\)
\(2-7\sqrt{3}\)
\(\frac{\sqrt[3]{128}}{\sqrt[3]{54}}\)
\(\frac{\sqrt{245x{y}^{-4}}}{\sqrt{45{x}^{-4}{y}^{3}}}\)
\(\frac{7{x}^{2}\sqrt{x}}{3|{y}^{3}|\sqrt{y}}\)
\(\frac{1}{\sqrt[3]{5}}\)
\(\frac{3}{2+\sqrt{3}}\)
\(3(2-\sqrt{3})\)
\(\sqrt{-4}·\sqrt{-9}\)
\(-4i(-2-3i)\)
\(-12+8i\)
\(\frac{4+i}{3-2i}\)
\({i}^{172}\)
\(1\)
In the following exercises, solve.
\(\sqrt{2x+5}+8=6\)
\(\sqrt{x+5}+1=x\)
\(x=4\)
\(\sqrt[3]{2{x}^{2}-6x-23}=\sqrt[3]{{x}^{2}-3x+5}\)
In the following exercise, ⓐ find the domain of the function ⓑ graph the function ⓒ use the graph to determine the range.
\(g(x)=\sqrt{x+2}\)
ⓐ domain: \([-2,\infty )\)
ⓑ
ⓒ range: \([0,\infty )\)
Glossary
- complex conjugate pair
- A complex conjugate pair is of the form a + bi, a – bi.
- complex number
- A complex number is of the form a + bi, where a and b are real numbers. We call a the real part and b the imaginary part.
- complex number system
- The complex number system is made up of both the real numbers and the imaginary numbers.
- imaginary unit
- The imaginary unit \(i\) is the number whose square is –1. i2 = –1 or \(i=\sqrt{-1}.\)
- standard form
- A complex number is in standard form when written as \(a+bi,\) where a, b are real numbers.